Selina Solutions Concise Maths Class 10 Chapter 9 Matrices

 

Selina Solutions Concise Maths Class 10 Chapter 9 Matrices

Salina Maths class 10 solutions Class 10 Chapter 9 Matrices have been provided to you through an online medium, using which you can understand the difficult questions of ICSE Class 10 Mathematics, and can prepare for the upcoming Board exam.

Selina Class 10 ICSE solution will give strength to you and the board will also clear the exam, Mathematics Subject demands time and practice, then keep practicing and you will definitely get success.

Exercise 9(A) Solutions

Exercise 9(B) Solutions

Exercise 9(C) Solutions

Exercise 9(D) Solutions

Access Selina Solutions Concise Maths Class 10 Chapter 9 Matrices Exercise 9(D)

Question 1. Find x and y, if:

Solution:

On comparing the corresponding terms, we have

6x – 10 = 8 and -2x + 14 = 4y

6x = 18 and y = (14 – 2x)/4

x = 3 and y = (14 – 2(3))/4

y = (14 – 6)/ 4

y = 8/4 = 2

Thus, x = 3 and y = 2

Question 2. Find x and y, if:

Solution:

On comparing the corresponding terms, we have

3x + 18 = 15 and 12x + 77 = 10y

3x = -3 and y = (12x + 77)/10

x = -1 and y = (12(-1) + 77)/10

y = 65/10 = 6.5

Thus, x = -1 and y = 6.5

Question 3. If;  ; find x and y, if:

(i) x, y ∈ W (whole numbers)

(ii) x, y ∈ Z (integers)

Solution:

From the question, we have

x2 + y2 = 25 and -2x2 + y2 = -2

(i) x, y ∈ W (whole numbers)

It can be observed that the above two equations are satisfied when x = 3 and y = 4.

(ii) x, y ∈ Z (integers)

It can be observed that the above two equations are satisfied when x = ± 3 and y = ± 4.

Question 4. 

(i) The order of the matrix X.

(ii) The matrix X.

Solution:

(i) Let the order of the matrix be a x b.

Then, we know that

Thus, for multiplication of matrices to be possible

a = 2

And, form noticing the order of the resultant matrix

b = 1

(ii)

On comparing the corresponding terms, we have

2x + y = 7 and

-3x + 4y = 6

Solving the above two equations, we have

x = 2 and y = 3

Thus, the matrix X is 

Question 5. Evaluate:

Solution:

Question 6.  3A x M = 2B; find matrix M.

Solution:

Given,

3A x M = 2B

And let the order of the matric of M be (a x b)

Now, it’s clearly seen that

a = 2 and b = 1

So, the order of the matrix M is (2 x 1)

Now, on comparing with corresponding elements we have

-3y = -10 and 12x – 9y = 12

y = 10/3 and 12x – 9(10/3) = 12

12x – 30 = 12

12x = 42

x = 42/12 = 7/2

Therefore,

Matrix M =

Question 7. 

find the values of a, b and c.

Solution:

On comparing the corresponding elements, we have

a + 1 = 5 ⇒ a = 4

b + 2 = 0 ⇒ b = -2

-1 – c = 3 ⇒ c = -4

Question 8. 

(i) A (BA) (ii) (AB) B.

Solution:

(i) A (BA)

(ii) (AB) B

Question 9. Find x and y, if: 

Solution:

Thus, on comparing the corresponding terms, we have

2x + 3x = 5 and 2y + 4y = 12

5x = 5 and 6y = 12

x = 1 and y = 2

Question 10. If matrix  find the matrix ‘X’ and matrix ‘Y’.

Solution:

Now,

On comparing with the corresponding terms, we have

-28 – 3x = 10

3x = -38

x = -38/3

And,

20 – 3y = -8

3y = 28

y = 28/3

Therefore,

Question 11. Given  find the matrix X such that:

A + X = 2B + C

Solution:

Question 12. Find the value of x, given that A2 = B,

Solution:

Thus, on comparing the terms we get x = 36.

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