Selina Solutions Concise Maths Class 10 Chapter 9 Matrices
Selina Solutions Concise Maths Class 10 Chapter 9 Matrices Exercise 9(B)
Question 1. Evaluate:
(i) 3[5 -2]
Solution:
3[5 -2] = [3×5 3x-2] = [15 -6]
(ii)
Solution:
(iii)
Solution:
(iv)
Solution:
Question 2. Find x and y if:
(i) 3[4 x] + 2[y -3] = [10 0]
Solution:
Taking the L.H.S, we have
3[4 x] + 2[y -3] = [12 3x] + [2y -6] = [(12 + 2y) (3x – 6)]
Now, equating with R.H.S we get
[(12 + 2y) (3x – 6)] = [10 0]
12 + 2y = 10 and 3x – 6 = 0
2y = -2 and 3x = 6
y = -1 and x = 2
(ii)
Solution:
We have,
So, equating the matrices we get
-x + 8 = 7 and 2x – 4y = -8
x = 1 and 2(1) – 4y = -8
2 – 4y = -8
4y = 10
y = 5/2
Question 3.
(i) 2A – 3B + C (ii) A + 2C – B
Solution:
(i) 2A – 3B + C
(ii) A + 2C – B
Question 4.
Solution:
Given,
Question 5.
(i) find the matrix 2A + B.
(ii) find a matrix C such that:
Solution:
(i) 2A + B
(ii)
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